the position x of a particle moving along a straight line is given by x=2-5t+6t*t find velocity and acceleration due to gravity
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4
x=2-5t+6t^2 m
v=dx/dt
v=d/dt(2-5t+6t^2)
v=12t-5 m/s
a=dv/dt
a=d/dt(12t-5)=12 m/s^2
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0
Answer:
12 m/s^2
Explanation:
- v=dx/dt
v= 0-5+2×2t
v=12t-5
v=24-5
v=19
a=dv/dt
a=d/dt(12t-5)
=12 m/s^2
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