Question

The position x of a particle moving in one dimension, under the action of constant force is related to time t by
equation x = (t - 3)^2
where x is in metre and t in sec. Calculate :
(a)
The displacement of the particle when its velocity is zero;

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Answer 1

Answer:

t=

x

+3

⇒

x

=t−3

x=t

2

−6t+9

dt

dx

is the velocity

⇒

dt

dx

=2t−6

v=0

2t−6=0

which will give us 3 so t=3

at t=3

⇒x=3−3

so, there will be 0 displacement.

Hence, the answer is 0.