Physics, asked by darkknight2129, 1 year ago

the position x of a particle varies with time T as X equals to 10 + 12t - 2t^2 where x in metre and T in second the distance travelled by the body in 5 second​

Answers

Answered by kk2116
1

Answer:

second the distance travelled

Answered by vikas3441
1

Answer:

26 metre

Explanation:

by differentiating the position wrt time

we get velocity at time t.

v=12-4t

putting v=0 we get ,when particle is at

rest ,that is t=3s

putting the limit in two parts

in .

X=10+12t-2t^2

first from t=0 to 3s

then t=3 to 5s

after taking the mod of them

we add them .

hence x=26 metre

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