the position x of a particle varies with time T as X equals to 10 + 12t - 2t^2 where x in metre and T in second the distance travelled by the body in 5 second
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Answered by
1
Answer:
second the distance travelled
Answered by
1
Answer:
26 metre
Explanation:
by differentiating the position wrt time
we get velocity at time t.
v=12-4t
putting v=0 we get ,when particle is at
rest ,that is t=3s
putting the limit in two parts
in .
X=10+12t-2t^2
first from t=0 to 3s
then t=3 to 5s
after taking the mod of them
we add them .
hence x=26 metre
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