Question

the position x of object changes with time t as x=t³-2t+8 where x is in meter and t is in second the net displacement of the object in the time interval of t=1s and t=3 is​

Answer 1

dx/dt= t³ - 2t + 8

dx = (t³ - 2t + 8) dt

ˣ₀∫dx = ₁³∫(t³ - 2t + 8) dt

x = (t⁴/4 - t² + 8t)₁³

x = (81/4 - 9 + 24) - (1/4 - 1 + 8)

x = (141/4) - (29/4)

x = 28

Hope It Helps !!!!!