Question

The positive square root 7-√48 is

Answer 1

Please see the attachment

Answer 2

$<b>Heya mate. (^_-). Solution below.$
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♣ Square root of 7 - √48

$= \sqrt{7 - \sqrt{48} }$


♦ We can write √48 as 4√3.



♠ Then,

$= \sqrt{7 - 4 \sqrt{3} }$


• Breaking 7 into two parts -

$= \sqrt{4 + 3 - 4 \sqrt{3} }$


• It can be written as -

$= \sqrt{( {2})^{2} + ({ \sqrt{3}) }^{2} - (2 \times 2 \times \sqrt{3}) }$


• Using identity : a² + b² - 2ab = (a - b)²,


$= \sqrt{(2 - \sqrt{3}) ^{2} }$


$= (2 - \sqrt{3}) ^{2 \times \frac{1}{2} }$


$= 2 - \sqrt{3}$



•°• √(7 - √48) = 2 - √3
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$<marquee>Thank you.</marquee>$