Question

the positive square root of 19+8root3​

Answer 1

Step-by-step explanation:

hi I am Kartik jaswal you

Answer 2

Answer:

Do you want: sqrt(19 - 8*sqrt(3))

Suppose that a and b are integers such that:

a + sqrt(b) = sqrt(19 - 8*sqrt(3))

(a + sqrt(b))^2 = 19 - 8*sqrt(3)

a^2 + 2a*sqrt(b) + b = 19 - 8*sqrt(3)

If we break up that equation into two equations, one for the rational part and one for the irrational part, we have:

a^2 + b = 19

2a*sqrt(b) = -8*sqrt(3)

From that, we get a = -4 and b = 3

So the answer is sqrt(3) - 4

But that's a negative number, if you want a non-negative number then use 4 - sqrt(3)

$❀✿THA᭄NKS★$