The positive square root of 7 √ 48 is
keerthika1998lekha:
pls can u xpln ur question
(C) 2 +√ 3 (D) 3 +√ 2
Answers
Answered by
161
7+√48 = 7+√4×4×3 = 7+4√3
let it is the square of a+√b. (there must be in that format or you can see from the options also. All are in a+√b format)
so (a+√b)² = 7+4√3
(a+√b)² = a²+b + 2a√b = 7+4√3
comparing the terms,
2a√b = 4√3
⇒ a√b = 2√3
a=2, b=3
and it satisfies a²+b = 7
So the required number is a+√b = 2+√3
let it is the square of a+√b. (there must be in that format or you can see from the options also. All are in a+√b format)
so (a+√b)² = 7+4√3
(a+√b)² = a²+b + 2a√b = 7+4√3
comparing the terms,
2a√b = 4√3
⇒ a√b = 2√3
a=2, b=3
and it satisfies a²+b = 7
So the required number is a+√b = 2+√3
Answered by
157
We have 7+√48
= 4+3+√4×4×3
= 2²+ (√3)²+2*2*√3
= (2+ √3)²
Hence the square root is +(2+√3)
= 4+3+√4×4×3
= 2²+ (√3)²+2*2*√3
= (2+ √3)²
Hence the square root is +(2+√3)
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