Question

The potential at a point A is -500V and that at another point B is +500V. What is the work done by external agent to take 2 units (S.I.) of negative charge from B to A ?

Answer 1

Here we will use the formula:
dW = Q.dV , where W= work done ; Q= charge (SI unit = coulomb); dV= potential difference
Integrating the above equation we get,
=> W - 0 = Q($V_{f} - V_{i}$);
=> W = 2.($V_{A} - V_{B}$);
=> W = 2.(-500 - 500);
=> W = -2000 J = - 2 kJ

Answer 2

Answer:

here is your answer

Explanation:

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