Question

The potential at a point is V = 5x + 8y – 2z.
What will be the electric field at that point ?​

Answer 1

Answer:

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Explanation:

Take partial derivatives with respect to each coordinate:

V = 5x -3x^2y + 2yz^2

Ex = -∂V/∂x = -[5 - 6xy] = -5 + 6xy

Ey = -∂V/∂y = -[-3x^2 + 2z^2] = 3x^2 - 2z^2

Ez = -∂V/∂z = -4yz