Question

The potential difference across the 3 ohm resistor in the following diagram is:

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Answer 1

Answer:

First find total current flow in the circuit, Current = Potential difference \ Total resistance.

Given in the question potential difference = 2 Volt

All resistance are connected in series combination so Total resistance is equal to summation of all resistance.

Total resistance = 6 ohm.

Now current = Potential difference in the circuit / total resistance

Current = 2/6 = 1/3 Ampere

Now  potential difference across 3 ohm resistor, V = IR.

so Potential difference across 3 ohm resistor V = 3*1/3 = 1 Volt.

Thank you, I hope this is helpful.

Bajrangee(Tutor of physics)  

 

Answer 2

Given:

A circuit with 3 resistors and a battery

The voltage of the battery = 2V

To Find:

The potential difference across the 3 Ω resistor.

Solution:

Let R1, R2, and R3 be the 1Ω , 3Ω, and 2Ω resistors respectively.

Since all the resistors are connected in series, the equivalent resistance of the circuit R = R1 + R2 + R3

or R = 6Ω

Using Ohm's Law, the net current in the circuit (i) = V / R

= 2 / 6

= 1/ 3 A

Since the resistors are in series, all the resistors receive the same current i.e 1/3 A

The potential difference across the 3 Ω resistor = V3 = i X R3

= 1 X 3 / 3 V

= 1 V

Hence, the potential difference across the 3 Ω resistor is 1 V.