The potential difference across the lamp in the diagram is 12V. How many joules of electricity energy are changed into light and heat when a charge of 1c,5c and a current of 2A flows through it for 10 seconds?
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Here we simply need to use, Work done = Potential difference × Charge to find the electrical energy utilised in the first two cases when we have the charge flowing. In the third case we can simply use, W = VIt
a. W = 12×1 = 12 J
b. W = 12×5 = 60 J
c. W = 12×2×10 = 240 J
a. W = 12×1 = 12 J
b. W = 12×5 = 60 J
c. W = 12×2×10 = 240 J
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