Question

the potential difference across the terminals of battwry is 50v when 11A current is drawn and 60v wheb 1A current is drawn .The emf and the internal resistance of the battery are​

Answer 1

Answer:

Let the potential drop across terminals be V = E - iR

Where E - emf and R - internal resistance

Using the given information

50V = E - 11R

60V = E - 1R

Solving the simultaneous equations

We get,

R = 1 ohm

E = 61V

Answer 2

Answer:

The emf of the battery will be equal to 61V and the internal resistance is 1Ω.

Explanation:

Consider that the 'r' is the internal resistance and 'E' is the emf and 'i' is the current.

Terminal potential $=E-ir$                     ...........(1)

When   $i=11A$ , put in eq.(1)

We get   $50=E-11r$                               ............(2)  

When   $i=1A$, put the value of $i$ in eq.(1),

           $60=E-r$                                      ............(3)

Subtract eq.(1) from (2)

    $60-50=E-r-E+11r$

           $10=10r$

  ∴        $r=1$Ω

Put the value of r in eq.(2),

  ∴      $50=E-11(1)\\ E=50+11\\ E=61V$

Therefore the emf and the internal resistance of the battery are 1Ω  and 61V respectively.​