. The potential difference between the terminals of a battery of e.m.f. 6.0V and internal resistance 1Ω drops to 5.8V when connected across an external resistor. Find the resistance of the external resistor
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Answer:
R1=I/R
R1=1/6 = 6
R2=1/5.8
R2=10/58
R2=5.8
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