the potential energy of a body of mass 0.5 kg increases by 100j when it is taken to the top of a tower from ground.if the force of gravity on 1kg is 10newton,what is the height of the tower? step by step answer please
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Solution-
Mass of body M=0.5kg
Potential energy P.E=100J
Force of gravity on 1 kg is 10 N
Now,
F=mg
10=1×g
g=10m/s
2
Now, change in Potential energy
=mg(h
2
−h
1
)
=mg(h−0)
=mgh
Now, the height is
100=mgh
h=
0.5×10
100
h=20m
Hence, the height of the tower is 20 m
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