Question

the potential energy of a long spring when stretched by 2cm is U. if the spring is stretched by 8cm the potential energy stored in its is​

Answer 1

Explanation:

potential energy stored in spring is proportional to displacement^2

U= k*2^2 = 4k

where k is constant of proportionality

when displacement is 8 cm

PE = k*8^2 = 64k = 16*4k

but 4k = U

therefore

PE =16U

Answer 2

Answer:

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