Question

The potential energy of a particle free to move along the x-axis is given by U(x)=(x(square)+1)J
Particle will be in equilibrium at

Answer 1

du/dx=0
and then d^2u/ dx^2 =0 ITS NEUTRAL
SO THE ANSWER WILL BE X=0

Answer 2

x=1i is the answer 1^2×-1=-1 +1=0 so potential energy will 0 i.e equilibrium state