Question

The potential energy of a particle moving along x-axis is given by U = 20 +5 sin (4πx), where
U is in J and x is in metre under the action of conservative forcer
(A) if total mechanical energy is 20 J. then at x = 7/8 m. particle is at equilibrium
(B) if total mechanical energy is 20 J. then at x = 7/8 m. particle
is not at equilibrium
(C) if total mechanical energy is 20 J. then at x = 3/8 m, particle is at equilibrium
(D) if total mechanical energy is 20 J. then at x = 3/8 m. particle is not a equilibrium​

Answer 1

Answer:

given =  U = 20 +5 sin (4πx),

to find = X

solution =

               U = 20 +5 sin (4πx) = -1

               Kmax = E - Umin

               Umin = 20 - 15

               Umin =  5 J

               4πX = 3/2 π, 7/2π

                X    =   3/8 , 7/8

from above  solution we can conclude that the statement A and C  is correct.

(A) if total mechanical energy is 20 J. then at x = 7/8 m. particle is at equilibrium            

 C) if total mechanical energy is 20 J. then at x = 3/8 m, particle is at equilibrium