Question

The potential energy of a particle of mass 100 g moving along x-axis is given by U = 5x(x-4):
in metre. The period of oscillation is
(1) 0.2π S
(2) 0.1π S
(3) π
(4)1/π​

Answer 1

Answer:

F= -dU/dx=20–10x.

Also F=0, in mean position.

So x=2 is the mean position.

For a displacement dx, F=F(x+dx)-F(x)=-10dx.

Comparing with F=-k dx , we get k=10.

Also m=0.1 kg.

Hence T=2 π(m/k)^1/2

= 2π/10

= π/5 second.