Question

The potential energy of a satellite of a satellite is -8 × 10⁹ J. What is its binding energy (or escape energy)?

Answer 1

Answer:

B.E.=$4\times10^{9}$

Explanation:

we know that binding energy=(Total energy of satellite in infinte orbit)-(Total energy of satellite in given orbit)

we know the total energy of satellite=$\frac{-GMm}{2(r+h)}$

where G=gravitational constant, M=mass of earth, m=mass of satellite, r=radius of earth, h=height of satellite.

for infinite orbit r+h tends to infinite and inverse of infinite is zero so T.E.in infinite orbit is zero.

So, B.E.=Total energy of satellite in given orbit.......................(1)

Total energy of satellite in given orbit=$\frac{-GMm}{2(r+h)}$.........(2)

P.E. of satellite=$\frac{-GMm}{r+h}$.....................(3)

so from (2) and (3) we have

T.E.=P.E./2

T.E.=(8 × 10⁹ J)/2

T.E.=$4\times10^{9}$....................................(4)

from (1) and (4)

B.E.=$4\times10^{9}$

Answer 2

Answer:

Potential energy = 2( binding energy )

binding energy = P.E. / 2

Binding energy = – 8 × 10^9 J / 2

Binding energy =  – 4 × 10^9 J