The potential energy of the electron present in the ground state of li2+ ion is represented by
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Ground state energy — The energy input required so that an electron is not part of the atom.
Lithium reacts by Loss of electron.
This energy required to remove an electron from the outermost energy level is known as Ionization energy.
Lithium has three electrons.
Li²⁺ is formed by Loss of two electrons.
The first ionization energy is 5.39eV
The second ionization energy is 75.64 eV
The third ionization energy is 122.45
Since Li²⁺ is formed by the second and first ionization energy, the energy input required to remove the remaining electron will be the 3rd ionization energy.
It is the ground state potential energy and is given by :
-122 eV
Explanation:
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ˆ
V
H-like atom
=
−
Z
e
2
4
π
ε
0
→
r
where:
Z
is the atomic number.
e
is the elementary charge,
1.602
×
10
−
19
C/particle
. The force of attraction for the nucleus with the electron is included in
ˆ
V
already, since
electron
−
e
⋅
protons
Z
e
=
−
Z
e
2
.
ε
0
=
8.854
×
10
−
12
F
⋅
m
−
1
is the vacuum permittivity.
→
r
is the radial distance of the electron from the nucleus.
We assume under the Born-Oppenheimer approximation that the nucleus can be treated as nearly stationary, so that the net charge of it is
Z
⋅
e
.
You know the atomic number of
Li
is
3
. So...
I think it’s helped you
V
H-like atom
=
−
Z
e
2
4
π
ε
0
→
r
where:
Z
is the atomic number.
e
is the elementary charge,
1.602
×
10
−
19
C/particle
. The force of attraction for the nucleus with the electron is included in
ˆ
V
already, since
electron
−
e
⋅
protons
Z
e
=
−
Z
e
2
.
ε
0
=
8.854
×
10
−
12
F
⋅
m
−
1
is the vacuum permittivity.
→
r
is the radial distance of the electron from the nucleus.
We assume under the Born-Oppenheimer approximation that the nucleus can be treated as nearly stationary, so that the net charge of it is
Z
⋅
e
.
You know the atomic number of
Li
is
3
. So...
I think it’s helped you
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