Question

The potential of a hydrogen electrode at pH10 is​

Answer 1

Answer:p H = 10

Using formula [H+] = 10-pH

So [H+]   = 10-10 M

Electrode reaction will be

H+ + e-   → ½ H2

Use the formula

Value of E0 = 0

Ecell = E0    -    0.0591  log[H2]

                         1            [H+]      

Ecell =    -    0.0591  log( 1/10-10)

                      1                

Ecell =     -    0.0591  ( 10)  = -0.591 V

Explanation:

Answer 2

The potential of the hydrogen electrode is -0.591 V.

Explanation:

Given: pH = 10

We know,

pH = -log[H+]

10 = -log[H+]

[H+] = -㏑(10)

[H+] = $10^{-10}$M

$E_{cell} = E^{o} - \frac{0.0591}{1} log \frac{[H_{2} ]}{[H^{+}]}$

E° = 0

$E_{cell} = 0 - \frac{0.0591}{1} log\frac{1}{10^{-10}}$

$E_{cell} = - \frac{0.0591}{1} \times 10$

$E_{cell} = -0.591 V$

The potential of the hydrogen electrode is -0.591 V.

To know more:

the potential of hydrogen electrode at pH=1 - Brainly.in

https://brainly.in/question/5796984

The potential of a hydrogen electrode at PH 10 is - Brainly.in

https://brainly.in/question/3656869