Question

the potentiometer consists of a wire of length 4m and resistance 10ohm. it is connected to a cell of e.m.f 2v the potential difference per unit length of the wire will be?

Answer 1

understood?
the potentiometer consists of a wire of length 4m and resistance 10ohm. it is connected to a cell of e.m.f 2v the potential difference per unit length of the wire will be?

Answer 2

Hey !

Given :

      Length of wire = 4 m

      Resistance, R = 10 Ω

           E.M.F (E) = 2V

Solution :

          Current in the wire, i = E/R = 2/10

                    = 0.2 A

∴ Potential difference per unit length of the wire

             = iR/I

             = 0.2 × 10 / 4

FINAL RESULT = 0.5 V/m

Good luck !