The power consumed by a heater P = VI, where V = (220 ± 2) V and I = (10 ± 0.4) A. The percentage error in P is
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P=VI
Therefore, percentage error in P will be,
∆P×100/P = ∆V×100/V + ∆I×100/I
= 2×100/220 + 0.4×100/10
= 200/220 + 40/10
= 0.9 + 4
= 4.9%
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