Question

The power dissipated in a resistance ‘R’ when connected across a battery of emf ‘V’ is?
a) V²/2R
b) V²/4R
c) V²/R
d) V²/3R

Answer 1

Answer:

Option c

Explanation:

It is the direct formula. ....

Answer 2

Answer:

Explanation:

Emf is nothing but the potential difference (V) between two objects

The formula for finding power is [ P = VI ] ---(1)

By Ohm's law, V=IR
or, I = $\frac{V}{R}$

Substituting in (1)

P = VI

P = V x $\frac{V}{R}$

$P = \frac{V^{2}}{R}$

Hence, the answer is option (c)

Hope this helps