Question

the power dissipated in the 5 ohm resistor is​

Answer 1

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Answer 2

Answer:

The power dissipated in the 5 ohm resistor is​ 5W.

Explanation:

As per the data given in the question,

Let current & voltage through 2Ω be $I_{1} \:and \:V_{1}$

and, effective current & voltage through 1Ω and 5Ω be $I_{2} \:and \:V_{2}$

so,

voltage across 2Ω

$V_{2} = I_{1} R \\V_{2}=3\times2\:\:\:(given)\\V_{2}=6V$

Now, voltage in parallel is same.

so, voltage across 1Ω and 5Ω will be 6V

Also, effective resistance in the 1Ω and 5Ω =1Ω +5Ω = 6Ω (series)

therefore current flowing throught effective resistance of 6Ω

$V_{2}=I_{2}R\\6=I_{2}\times6\\I_{2}=1A$

Now, since current in 1A so, voltage across 5Ω

$V=I_{2}R\\V=1\times5\\V=5$

Since V across 5Ω  is 5V

So, power will be

$P=\frac{V^{2}}{R}\\ P=\frac{5\times 5}{5} \\P=5W$

Hence, the power dissipated in the 5 ohm resistor is​ 5W.

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