Physics, asked by smittandel61, 6 months ago

.The power input to 415 V , 50 Hz , 3 phase induction motor running at 975 rpm is 40 kW. Stator losses are 1 kW.Friction and windage losses are 2 kW.the efficiency of motor is ________________.

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Answered by subhamsubudhi
0

Answer:

Answer:Explanation:power i/p = 40 kw Slip = 0.025 Rotor i/p = 40 – 1 = 39 kw GMPO = (1 - S) 39 = 38.025 kw Shaft o/p = 38.025 – 2 = 36.025 kw

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