Question

The power of a lens is -4.0 D. A virtual and erect image is obtained at 5 cm from it. Find the position of the objet
and height of the image.​

Answer 1

Answer:

Answer: Given,

Power of lens (P) = – 2.0 D

Thus, focal length (f) =?

We know that, P = 1/f

Or, – 2.0 D = 1/f

Or, f = 1/– 2.0 D

Or, Focal length (f) = – 0.5 m

Since, power of length is in minus, thus it is a concave lens.

Explanation:

Ans ✔✔✔✔

Answer 2

Answer:

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