the power of septacal lens of 2 daiopeter the focal length will be
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power of lens=1/focal length
=2=1/f
=2f=1
=f=1/2
=f=0.5cm
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P = 1/f
where f is focal length
P = 2D
2 = 1/f
f = 1/2
f = 0.5 m
Remember: take focal length in m.
If Focal length is given in cm and you need to find the Power then
P = 100/f....
Thank you
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