Physics, asked by as5773716ozf29j, 1 year ago

the power of septacal lens of 2 daiopeter the focal length will be​

Answers

Answered by botanyliker
0

power of lens=1/focal length

=2=1/f

=2f=1

=f=1/2

=f=0.5cm

Answered by riyatalukdar231100r
0

P = 1/f

where f is focal length

P = 2D

2 = 1/f

f = 1/2

f = 0.5 m

Remember: take focal length in m.

If Focal length is given in cm and you need to find the Power then

P = 100/f....

Thank you

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