Math, asked by janhavi5323, 1 year ago

The poynting vector of an electromagnetic wave in vacuum is S={(120W/m^2) sin^2[(8.0 rad/m) z+ (2.4*10^9 rad/s) t]} k what is the wavelength?

Answers

Answered by topanswers
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Given:

Poynting vector, s = ( 120 w / m^2 ) sin^2 ( 8.0 rad / m ) z + ( 2.4 * 10^9 rad / s  ) t ) k

To find:

The wavelength.

Solution:

The equation of the electromagnetic wave,

E = E₀ sin^2 ( k x - w t ) i

Comparing,

We get,

k = 8

Hence,

Wavelength = 2 * π / k

π - 3.14

Substituting,

We get,

2 * 3.14 / 8

Hence, Wavelength = 0.3925 m

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