the premiter of a square is double that of a rectangle.lf perimeter of the square is 120m and length and breadth of the rectangle are in the ratio 3:2 find the breadth of the rectangle.
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Let the length of rectangle be 3x and breadth be 2x.
Perimeter of rectangle is = 2(3x+2x)= 10x
Given Perimeter of square is 120m
Perimeter of rectangle is 60m.
Equating 10x= 60, we get x= 6.
Breadth of rectangle is 12m.
radhika116:
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Hey there!!!
Here is the solution
===================
Given:-
Perimeter of square is double that of rectangle
Let perimeter of square be x and perimeter of rectangle be y
then,
X = 2Y_(1)
given :- X = 120m
put this in eq(1)
120 = 2Y
Y = 60m
Now , we have to find breadth of rectangle..
length and breadth of rectangle are in the ratio 3:2
we can take it as 3a and 2a
perimeter of rectangle = 2(l+b)
60 = 2(3a+2a)
60 = 10a
a = 6m
breadth is = 2a = 2×6 = 12m
Hope it helps you out✔✔
Here is the solution
===================
Given:-
Perimeter of square is double that of rectangle
Let perimeter of square be x and perimeter of rectangle be y
then,
X = 2Y_(1)
given :- X = 120m
put this in eq(1)
120 = 2Y
Y = 60m
Now , we have to find breadth of rectangle..
length and breadth of rectangle are in the ratio 3:2
we can take it as 3a and 2a
perimeter of rectangle = 2(l+b)
60 = 2(3a+2a)
60 = 10a
a = 6m
breadth is = 2a = 2×6 = 12m
Hope it helps you out✔✔
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