Question

The present age of A and B are in the ratio 7 is to 5 10 years later there the ages will be in the ratio 9 is to 7 find the present age

Answer 1

let them be 7x nd 5x
atq
7x+10/5x+10=9/7
7(7x+10)=9(5x+10)
49x+70=45x+90
49x-45x= 90-70
4x=20
x=20/4
x=5
now ages, a= 7×5
35
b= 5×5
25
hope this helps u.......
.i am in 8th class
in which class u r in

Answer 2

Question :-

●The present age of A and B are in the ratio 7 is to 5. 10 years later there the ages will be in the ratio 9 is to 7 find the present age.

Given :-

●The present age of A and B is 7:5

●Their age will be in the ratio 9:7

To find :-

●their present ages

Solution :-

●Let the present age of A and B be 7x and 5x.

●After 10 yrs , their ages will be (7x+10) and (5x+10).

●According to the given condition,

(7x+10) : (5x+10) = 9 : 7

I.e.

$\frac{7x + 10}{5x + 10} = \frac{9}{7} \\ by \: cross \: multiplication \: we \: get$

7(7x+10) = 9(5x+10)

49x + 70 = 45x + 90

49x-45x = 90 - 70

4x = 20

x = 5

●Present age of A = 7x = 7×5= 35 yrs

●Present age of B = 5x = 5×5= 25 yrs