Question

The present age of a father is equal to the square of the present age of his son. One year ago, the
of the father was 8 times the age of his son. Find their present ages.
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Answer 1

Answer:

Step-by-step explanation:

Let the present age of father be x and son be y

Age one year ago will be x-1 and y-1

x = y²   -------------(1)

(x-1) = 8(y-1) ---------(2)

Substitute x = y² in (2)

y² - 1 = 8y -8

y²-8y + 7 = 0

y² - 7y -y +7 = 0

y(y-7) - 1(y-7) = 0

(y-1)(y-7) = 0

y=1 or 7

So y = 7 and x=49

Father's age = 49

Son's age = 7.

Answer 2

Done.hope it helps u