Math, asked by Nikhil321890, 2 months ago

The present age of a father is equal to the sum of the ages of his two sons •6 years ago the average of the three is 34 years .If the present age of 2nd son is twice to the present age of 1st son .Find the ratio of three after 10 years .father is to 1st son is to 2nd son with full explanation ?​

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Answered by Anonymous
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Answer:

The present age of a father is equal to the sum of the ages of his two sons •6 years ago the average of the three is 34 years .If the present age of 2nd son is twice to the present age of 1st son .Find the ratio of three after 10 years .father is to 1st son is to 2nd son with full explanation ?

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