Question

The present age of a father is three years more than three times the age of the son. Three years hence father’s age will be 10 years more than twice the age of the son. Determine their present ages.

Answer 1

$\huge\mathcal{\underline{Question:-}}$

The present age of a father is three years more than three times the age of the son. Three years hence father’s age will be 10 years more than twice the age of the son. Determine their present ages. ?

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$\huge\mathcal{\underline{Solution:-}}$

★ Let the son's age be x

Then , according to the condition,

• father's age =3x+3

3 years later:

• Son's age =x+3

• Father's age =3x+3+3=3x+6

According to the condition given ,

• 3x+6 = 10+2(x+3)

• 3x+6=10+2x+6

• x=10

Thus , the son's present age is 10 years and the father's age is

Thus , the son's present age is 10 years and the father's age is3x+3=3×10+3=33 years.

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Answer 2

Given :-

The present age of a father is three years more than three times the age of the son . Three years hence father's age will be 10 years more than twice the age of the son .

To Find :-

Present ages

Solution :-

Let the age of son be x and father age will be 3x + 3

After 3 years

Age of son = x + 3

Age of father = 3x + 3 + 3 = 3x + 6

Now

ATQ

3x + 6 = 10 + {2(x + 3)}

3x + 6 = 10 + 2x + 6

3x + 6 = 16 + 2x

3x - 2x = 16 - 6

x = 10

Age of son = 10 years

Age of father = 3(10) + 3 = 33 years