Question

The present age of a father is three years more than three times the age
of his son. Three years hence the father's age will be 10 years more than
twice the age of the son. Determine their present ages.​

Answer 1

Answer:

Let the age of son be x

Father 3x+3

Step-by-step explanation

Answer 2

Answer:

let present age of son=x

present age of father=3x+3

3 years hence,

father's age=3x+6

son's age=x+3

according to question

3x+6=2(x+3)+10

3x+6=2x+6+10

3x+6=2x+16

3x-2x=16-6

x=10

therefore

present age of son=10

present age of father=3x+3=33

hope it helps

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