Question

The present age of a father is three years more than three times the age of the son. Three years hence, the father's age will be 10 years more than twice the age of the son. Determine their present ages.

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Answer 1

Answer:

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Answer 2

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Let the son's age be x

Then , according to the condition,

father's age =3x+3

3 years later:

Son's age =x+3

Father's age =3x+3+3=3x+6

According to the condition given ,

3x+6=10+2(x+3)

3x+6=10+2x+6

x=10

Thus , the son's present age is 10 years and the father's age is

3x+3=3×10+3=33 years.