Question

The present age of a father is three years more than three times the age of his son.three years hence,father's age will be 10 years more than twice the age of the son.determine their present ages

Answer 1

Let father's present age be x yrs.
Let his son's present age be y yrs.
A/Q, x = 3 + 3y
x - 3y = 3 ..... (1)

After 3 years, x +3 = 10 + 2(y+3)
x + 3 = 10 + 2y +6
x -2y = 10+6 - 3
x - 2y = 13 .... (2)
Solving the pair of linear equations, by elimination

x -3y = 3
x - 2y = 13
- + -
---------------------
-y = -10
y = 10
This gives, x = 33

So, father's present age is 33 yrs
His son's present age is 10 yrs