Question

The present age of a man is 7 times the present age of his son if two years ago the age of the man was 11 times the age of the son and the present age of man is

Answer 1

Son's age = a

Man's age = 7a

Before 2years

Son's age = a - 2

Man's age = 11(a-2)

7a - 2 = 11a - 22

4a = 20

a = 5

Son's present age = 5years

Man's age = 35years

Answer 2

Present Age of Man = 35 Years

Given Terms:

• Present age of man is 7 times the present age of his son.
• Two years ago age of man was 11 times the age of son.

Need To Find:

• Present age of man is ?

Solution: Let present age of son is y years and of man is x years .

=> Present age of man = 7 times of y

=> x = 7y years.

{ Two years ago }

=> Age of man = 11 times the age of son.

=> (x – 2) = (y – 2) × 11

Solving the equation

➥ (x – 2) = 11 × (y – 2)

➥ (x – 2) = 11y – 22

➥ 7y – 2 + 22 = 11y

➥ 20 = 11y – 7y

➥ 20/4 = y

➥ 5 = y

We have got earlier that man's present age is equal to x = 7y years. Then x = 7 × 5 = 35 years.

Required age of man is 35 years.