Math, asked by tsiri9999, 9 months ago

The present age of a man is seven times the present age his son. Two years ago, the age of the man was eleven times the age of the son. Find the present age of the man (in years)

Answers

Answered by rajdheerajcreddy
0

Answer:

28 years.

Step-by-step explanation:

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Answered by Anonymous
1

Answer:

let sons present age be x

present age of men be 7x

2 years ago their ages are

7x - 2 , x -2

7x - 2 = 11(x - 2)

7x - 2 = 11x - 22

22 -2 = 11x - 7x

20 = 4x

x = 5

present age of men is

7 * 5 = 35 years

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