Question

the present age of a man is twice that of his don. 8 years hence, their ages will be in the ratio 7:4. find their present ages

Answer 1

Answer:

Answer is in attachment

Answer 2

Answer: 24 and 48

Step-by-step explanation:

Given,

Present age of man is twice of his son (it's not don)

Let the son be x

Then the man age is 2*x=2x

8 years hence(later)

Son's age is x+8

Man's age is 2x+8

Ages are in ratio 7:4

According to the problem,

The mathematical equation is

2x+8/x+8=7/4

4(2x+8)=7(x+8)

8x+32=7x+56

8x-7x=56-32

x=24

Son's age is x = 24 years

Man's age is 2x = 24×2

= 48 years

Hope this helps you

(^_^)