The present age of a man is twice that of his son. Ten years hence their ages will be in the ratio 8:5. Find the present age of his son.
Answers
Answered by
171
Solution:
➡ Let the present age of the son be x years.
➡ Then, the present age of the father is 2x years.
Ten years hence,
➡ Age of son will be (x + 10) years
➡ Age of father will be (2x + 10) years
From the question,
Hence, the present age of the son is 15 years
Answered by
25
Given that,
↝ The present age of a man is twice that of his son.
Let assume that
Present age of son be 'x' years.
So,
Present age of Father '2x' years.
So, we have
Further given that,
↝ Ten years hence their ages will be in the ratio 8:5.
So, After 10 years
According to statement
Hence,
▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬
Basic Concept Used :-
Writing Systems of Linear Equation from Word Problem.
1. Understand the problem.
- Understand all the words used in stating the problem.
- Understand what you are asked to find.
2. Translate the problem to an equation.
- Assign a variable (or variables) to represent the unknown.
- Clearly state what the variable represents.
3. Carry out the plan and solve the problem.
Similar questions