Math, asked by Guriyasah74, 6 months ago

The present age of a son is half the present age of his father. Ten years ago

the father was thrice as old as his son. What are their present age?​

Answers

Answered by Buta5146
30

Step-by-step explanation:

Given that,

The present age of son is half the present age of his father.

Let the present age of the father be 2x.

Therefore present age of the son = 2x/2 = x years

ATQ,

10 years ago, father's age was thrice as old as his son.

➡ 3(x - 10) = 2x - 10

➡ 3x - 30 = 2x - 10

➡ 3x - 2x = -10 + 30

➡ x = 20

Hence their present ages are :-

Father's present age = 2x = 40 years

His son's present age = x = 20 years

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Answered by roshnisherpa03
0

Answer:

Step-by-step explanation:

Given that,

The present age of son is half the present age of his father.

Let the present age of the father be 2x.

Therefore present age of the son = 2x/2 = x years

ATQ,

10 years ago, father's age was thrice as old as his son.

➡ 3(x - 10) = 2x - 10

➡ 3x - 30 = 2x - 10

➡ 3x - 2x = -10 + 30

➡ x = 20

Hence their present ages are :-

Father's present age = 2x = 40 years

His son's present age = x = 20 years

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