Question

the present age of a woman is 3 years more than 3 times the age of a Daughter 3 years hence the women's age will be 10 years more than twice the age of her daughter find their present age

Answer 1

this is the solution

Answer 2

Answer:

The present age of woman is 33 years

And daughter's age is 10 years.

Step-by-step explanation:

Let the present age of a woman is x

And the present  age of her daughter is y.

the present age of a woman is 3 years more than 3 times the age of a Daughter 3 years  that means:

$x=3+3y$

$\Rightarrow x-3y=3$ (1)

And also, 3 years hence the women's age will be 10 years more than twice the age of her daughter that means:

$x+3=10+2(y+3)$

$\Rightarrow x+3=10+2y+6$

$\Rightarrow x-2y=13$   (2)

On solving (1) and (2) by subtracting (2) from (1)

Sign of (2) changes we get:

$-x+2y=-13$  (4)

Now, solving(1) and (4) we get:

$-y=-10$

$y=10$

Substitute y=10 in (1) we get:

$x-3(10)=3$

$x=33$

So, the present age of woman is 33 years

And daughter's age is 10 years.