Math, asked by sindhu18, 1 year ago

the present age of Amit and Rahul are in the ratio 15:8.
after 10 years their age will be in the ratio 5:3
Find their present ages


plz answer fast..

Answers

Answered by raiyaanafs786pd4pmv
44
Let their present ages be 15x and 8x .
After 10 years :
Amit's age = 15x + 10
Rahul's age = 8x + 10
So, ATQ
15x + 10 / 8x +10 = 5/3
45x + 30 = 40x + 50
x = 4
their present ages = 60 yrs and 32 yrs
Answered by bharathparasad577
0

Answer:

Present  age of Amit = 75 years  and Present age of Rahul = 40 years

Step-by-step explanation:

Given:

Ratio of Amit's and Rahul's present age =  15 : 8    ⇒ A

Ratio of Amit's and Rahul's age after 10 years =  5 : 3  ⇒  B

To find:

Present ages of Amit and Rahul

Solution:

Step 1:

From A,

Present age of Amit and Rahul is 15x and 8x.

From B,

After 10 years, ages of Amit and Rahul be 15x+10  and 8x+10

Step 2:

(15x+10) : (8x+10) = 5:3\\\\\frac{15x+10}{8x+10} = \frac{5}{3} \\\\3(15x+10)=5(8x+10)\\45x+30 =40x+50\\45x-40x = 50-30\\5x=20\\x=\frac{20}{4}\\ x=5\\

Step 3:

Substitute value of 'x' in A,
Present age of Amit is 15x

    =15*5\\=75\\

Present age of Rahul is 8x

=8*5\\=40

Hence present ages of Amit is 75 years

and  present ages of Rahul is 40 years\\

Project code:#SPJ3

Similar questions