Math, asked by aaabhishek2728, 10 months ago

The present age of arif's mother is three times the present age of arif. After five years their ages will be add to 66.find their present ages.

Answers

Answered by kalpana2932
4

Answer:

let arifs age be x

x+5=x-66

taking 66 to LHS

x+5+66=3x

taking x to RHS

71=3x-x

71=2x

taking 2 to LHS

71/2=x

35.5=x

Answered by Anonymous
1

  \huge{ \boxed{ \underline{ \mathfrak{ \dag{Question}}}}}

The present age of Sahil’s mother is three times the present age of Sahil. After 5 years their ages will add to 66 years. Find their present ages.

  \huge{ \boxed{ \underline{ \mathfrak{ \dag{Answer:-}}}}}

Assume present age of sahil be x

Present age of his mother will be 3x

after 5 years

sahil age=x+5

his mothers age =3x+5.

According to question

(x+5)+(3x+5)=66

4x+10=66

4x=56

x=14

sahil present age=14 years

his mother present age= 42 years.

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