the present age of beena is 2 years more then reeta the present age of Tina is 3 years more than been if the sum of the ages of Rita ,beena and teena is 79 years find the present age of all the three of them
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Let the age of reeta be X yrs.
Given that the age of beena is 2 years mote than that of reeta.
So, the age of beena is (X+ 2) yrs.
Given that the age of teena is 3 years more than that of beena.
so, the age of teena is [(X+2) + 3] = (X+5) yrs.
Given the sum of ages of rita, beena and teena is 79 yrs.
=> X+ (X+2) + (X+5) = 79
3X + 7 = 79
3X = 79 - 7
3X = 72
X = 72/3
X = 24
So, the age of reeta = X yrs = 24 yrs.
the age of beena = (X+2) yrs = (24+2) yrs = 26 yrs.
the age of teena = (X+5) yrs = (24+5) yrs = 29 yrs.
Hope this answer helps you.
Given that the age of beena is 2 years mote than that of reeta.
So, the age of beena is (X+ 2) yrs.
Given that the age of teena is 3 years more than that of beena.
so, the age of teena is [(X+2) + 3] = (X+5) yrs.
Given the sum of ages of rita, beena and teena is 79 yrs.
=> X+ (X+2) + (X+5) = 79
3X + 7 = 79
3X = 79 - 7
3X = 72
X = 72/3
X = 24
So, the age of reeta = X yrs = 24 yrs.
the age of beena = (X+2) yrs = (24+2) yrs = 26 yrs.
the age of teena = (X+5) yrs = (24+5) yrs = 29 yrs.
Hope this answer helps you.
kisu9:
answer is right
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