Math, asked by Anonymous, 1 year ago

the present age of farhaan is four times thee present age of Robin. 7years ago their ages added to 36 years. find their present ages

Answers

Answered by BEJOICE
1
Let present age of Robin be x
Then, present age of Farhan is 4x
7 years ago,
(x - 7) + (4x - 7) = 36 \\ 5x - 14 = 36 \\ 5x = 50 \\ x = 10
So present ages are 10 and 40
Answered by MissKalliste
1

Appropriate Question:

The present age of Farhaan is four times the present age of Robin. Seven years ago, their ages will add up to 36 years. Find their present ages.

Answer:

\fbox\green{\sf Robin's\:age = 10\:years}

\fbox\green{\sf Farhaan's\:age = 14\:years}

Step-by-step explanation:

\leadsto\underline\mathtt\red{Letting\:their\:age:-}

  • Age of Robin = x
  • Age of Farhaan = 4x

\leadsto\underline\mathtt\red{Seven\:years\:ago:-}

  • Age of Robin = (x - 7)
  • Age of Farhaan = (4x - 7)

\mapsto\underline\mathtt\green{Equation:-}

:\implies\textsf{(x-7)+(4x-7)=36}

:\implies\textsf{x-7+4x-7 = 36}

:\implies\textsf{5x-14=36}

:\implies\textsf{5x=36+14}

:\implies\textsf{5x=50}

:\implies\sf{x= \cancel{\dfrac{50}{5}}}

:\implies\fbox\red{\sf x = 10}

\leadsto\underline\mathtt\red{Putting\:the\:value\:of\:x:-}

  • Robin's age = x = 10 years
  • Farhaan's age = 4x = 4(10) = 40 years

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