Math, asked by suraj5912, 10 months ago

the present age of father is double of the age of his son if the difference of their ages is 25 years find their ages​

Answers

Answered by moshnetic
2

Answer:

father's age is 50 and son's age is 25

Step-by-step explanation:

let son ' s age = x

father's age is double of son's age

=> father's age = 2 * x

= 2x

difference in father's age and son's age is 25 years

=> 2x - x = 25

=> x = 25

=> 2x = 50

so the son's age is 25 and father's age is 50

Answered by Mysterioushine
4

GIVEN:

• PRESENT AGE OF FATHER IS DOUBLE THE AGE OF HIS SON AND DIFFEREENCE IS 25 YEARS

TO FIND :

• THE AGE OF FATHER AND SON

SOLUTION:

LET THE PRESENT AGE OF THE SON BE X THEN HIS FATHER'S AGE = 2X

ACCORDING TO THE QUESTION ,

=> 2X - X = 25

=> X = 25

∴ THE SON AGE (X) = 25

THE FATHER AGE (2X) = 50

HOPE IT HELPS !!!!

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