Math, asked by suraj5912, 8 months ago

the present age of father is double of the age of his son if the difference of their ages is 25 years find their ages​

Answers

Answered by moshnetic
2

Answer:

father's age is 50 and son's age is 25

Step-by-step explanation:

let son ' s age = x

father's age is double of son's age

=> father's age = 2 * x

= 2x

difference in father's age and son's age is 25 years

=> 2x - x = 25

=> x = 25

=> 2x = 50

so the son's age is 25 and father's age is 50

Answered by Mysterioushine
4

GIVEN:

• PRESENT AGE OF FATHER IS DOUBLE THE AGE OF HIS SON AND DIFFEREENCE IS 25 YEARS

TO FIND :

• THE AGE OF FATHER AND SON

SOLUTION:

LET THE PRESENT AGE OF THE SON BE X THEN HIS FATHER'S AGE = 2X

ACCORDING TO THE QUESTION ,

=> 2X - X = 25

=> X = 25

∴ THE SON AGE (X) = 25

THE FATHER AGE (2X) = 50

HOPE IT HELPS !!!!

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