Question

the present age of father is four times olf his son. after, 10 years age of father will become three times the age of the son. find their present ages.

Answer 1

Let the age of son be x.
Father's age= 4x
After 10 years,
Son's age = x+10
Father's age = 4x+10
4x+10=3(x+10)
4x+10=3x+30
4x-3x=30-10
x=20
Son's age =20
Father's age=4×20
=80

Answer 2

let the age of son be x years.
Present age of father (y) = 4x years.

After 10 years,
son's age = (x+10) years
father's age = (4x+10) years
However, given after 10 years, father's age = 3(x+10) = (3x+30) years

ACCORDING TO PROBLEM,
(4x+10) = (3x+30)
=> 4x-3x = 30-10
=> x = 20

Therefore, son's age = 20 years
Hence, father's age = 4x years = (4×20) years = 80 years.