Math, asked by arnav3315, 8 months ago

The present age of father is four times that of his son. Six years hence, the age of
father will be thrice that of his son. Find their present ages.

Answers

Answered by saifreza12345678
7

Answer:

son's age= 12 years

and father's age = 48 years

Step-by-step explanation:

let the age of this father's son be x

fathers present age = 4x

after 6 years

sons age = X + 6

father's age = 4 x + 6

but also father's age equals 3(x+6)

=3x+18

according to question

3 X + 18 = 4 x + 6

3 x - 4 x = 6 -18

- x = -12

x = 12

so according to the question

son's present age is 12(given in the first line "x"=12)

and father's present age is 48 (given in the second line"4x"=4*12=48)

thanks for asking the question.

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